On Mon, Feb 2, 2015 at 6:20 AM, Steven D'Aprano <steve+comp.lang.pyt...@pearwood.info> wrote: > Devin Jeanpierre wrote: >> Oops, I just realized why such a claim might be made: the >> documentation probably wants to be able to say that any method can use >> super(). So that's why it claims that it isn't a method unless it's >> defined inside a class body. > > You can use super anywhere, including outside of classes. The only thing you > can't do is use the Python 3 "super hack" which automatically fills in the > arguments to super if you don't supply them. That is compiler magic which > truly does require the function to be defined inside a class body. But you > can use super outside of classes:
Obviously, I was referring to no-arg super. Please assume good faith and non-ignorance on my part. -- Devin -- https://mail.python.org/mailman/listinfo/python-list
