On 28/01/2015 15:50, stephen.bou...@gmail.com wrote:
> I am using the following to open a file in its default application in
> Windows 7:
>
> from subprocess import call
>
> filename = 'my file.csv' call('"%s"' % filename, shell=True)
>
> This still leaves a python process hanging around until the launched
> app is closed. Any idea how to get around?
>
This is somewhat clumsy. The built-in way is:
import os
os.startfile("my file.csv")
TJG
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