On Sat, Jan 24, 2015 at 2:14 PM, Mario Figueiredo <mar...@gmail.com> wrote: > In article <54c39366$0$13006$c3e8da3$54964...@news.astraweb.com>, > steve+comp.lang.pyt...@pearwood.info says... >> > AttributeError: 'Sub' instance has no attribute '__bases__', >> > AttributeError: 'foo' object has no attribute '__bases__' >> >> The first would be nice. The second is impossible: objects may have no name, >> one name, or many names, and they do not know what names they are bound to. >> So the Sub instance bound to the name 'foo' doesn't know that its name >> is 'foo', so it cannot display it in the error message. > > Thanks for the information! :) > > But that begs the OT question:
No, it doesnt. http://en.wikipedia.org/wiki/Begging_the_question > How does Python maps names to memory > addresses in the interpreter? Global variables are looked up in the current stack frame's globals dict. >>> a = 1 >>> b = 2 >>> globals()['a'] 1 >>> globals()['b'] 2 Local variables of functions could be handled the same way, but for efficiency the compiler instead maps the names to indices of a local variable array associated with the stack frame. Either way, at the C level the value stored in the dict or array is a pointer to the memory location of the object. > "__main__" > from module import a_name > y = a_name + 1 > > How does python interpreter know how to map 'name' to the correct memory > location, if this __main__ code is only ran after 'module' code? I'm not sure I'm understanding what you're asking, but the import statement imports the module, looks up "a_name" in that module's globals dict, and binds the same object to a_name in the current module's globals dict. -- https://mail.python.org/mailman/listinfo/python-list
