Given a matrix I want to shift the 1st column 0 (ie leave as is) 2nd by one place, 3rd by 2 places etc.
This code works. But I wonder if numpy can do it shorter and simpler. --------------------- def transpose(mat): return([[l[i] for l in mat]for i in range(0,len(mat[0]))]) def rotate(mat): return([mat[i][i:]+mat[i][:i] for i in range(0, len(mat))]) def shiftcols(mat): return ( transpose(rotate(transpose(mat)))) >>> mat = [[1,2,3,4,5,6], [7,8,9,10,11,12], [13,14,15,16,17,18], [19,20,21,22,23,24], [25,26,27,28,29,30], [31,32,33,34,35,36], [37,38,39,40,41,42]] >>> shiftcols(mat) [[1, 8, 15, 22, 29, 36], [7, 14, 21, 28, 35, 42], [13, 20, 27, 34, 41, 6], [19, 26, 33, 40, 5, 12], [25, 32, 39, 4, 11, 18], [31, 38, 3, 10, 17, 24], [37, 2, 9, 16, 23, 30]] I was hoping for something like the following APL operator >>> mat 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 >>> 0 1 2 3 4 5 ⊖ mat 1 8 15 22 29 36 7 14 21 28 35 6 13 20 27 34 5 12 19 26 33 4 11 18 25 32 3 10 17 24 31 2 9 16 23 30 -- https://mail.python.org/mailman/listinfo/python-list