As yield is an expression, it's legal in a lambda function, which then means you have a generator function. But it's not quite the same as the equivalent function made with def:
$ python3 Python 3.5.0a0 (default:1c51f1650c42+, Dec 29 2014, 02:29:06) [GCC 4.7.2] on linux Type "help", "copyright", "credits" or "license" for more information. >>> f=lambda: (yield 5) >>> x=f() >>> next(x) 5 >>> x.send(123) Traceback (most recent call last): File "<stdin>", line 1, in <module> StopIteration >>> def f(): return (yield 5) ... >>> x=f() >>> next(x) 5 >>> x.send(123) Traceback (most recent call last): File "<stdin>", line 1, in <module> StopIteration: 123 Is this a bug? I very much doubt any sane code will ever run into this; I discovered this purely by chance, after noting that Python/compile.c had code to create a generator. The same thing happens with Python 3.4.2 on Debian Jessie, so this isn't a bug I've introduced in my local fiddling around. If nothing else, it's an amusing proof that you shouldn't just stuff every cool thing you can think of into a single line of code :) ChrisA -- https://mail.python.org/mailman/listinfo/python-list
