I am defining a single class with a destructor method that prints ‘__del__’,
and running that source code string using exec with the module’s dict like so:
import rtmidi
import sys
import types
import time
import gc
s = """
class A:
def __del__(self):
print('__del__')
a = A()
"""
m = types.ModuleType('mine')
exec(s, m.__dict__)
print('deleting...')
m = None
print('done')
and the output is:
deleting...
done
__del__
I the “__del__" to come between “deleting…” and “done”. This is not being run
from the interactive interpreter by via a .py file.
> On Nov 23, 2014, at 12:56 AM, Ian Kelly <ian.g.ke...@gmail.com> wrote:
>
> On Sun, Nov 23, 2014 at 2:48 AM, Ian Kelly <ian.g.ke...@gmail.com> wrote:
>> On Sat, Nov 22, 2014 at 11:49 PM, Patrick Stinson <patrickk...@gmail.com>
>> wrote:
>>> If I create a module with imp.new_module(name), how can I unload it so that
>>> all the references contained in it are set to zero and the module is
>>> deleted? deleting the reference that is returned doesn’t seem to do the
>>> job, and it’s not in sys.modules, so where is the dangling reference?
>>
>> How are you determining that the module is not deleted?
>
> From my testing, using Python 3.4:
>
>>>> for i in range(5): imp.new_module('spam')
> ...
> <module 'spam'>
> <module 'spam'>
> <module 'spam'>
> <module 'spam'>
> <module 'spam'>
>>>> import gc, types
>>>> [m for m in gc.get_objects() if isinstance(m, types.ModuleType) and
>>>> m.__name__ == 'spam']
> [<module 'spam'>]
>>>> 42
> 42
>>>> [m for m in gc.get_objects() if isinstance(m, types.ModuleType) and
>>>> m.__name__ == 'spam']
> []
>
> In this case one of the created modules was hanging around because it
> was still referenced by the special "_" variable of the interactive
> interpreter. Evaluating a new expression cleared that out and deleted
> the module. Maybe you're seeing the same thing.
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