Grant Edwards <invalid@invalid.invalid> writes:
[...]
> With link-local addresses you also need to specify which interface to
> use. The normal way of doing this on Linux with command-line utilities
> is append %<ifname> to the address/hostname (e.g. ping6 ff02::1%net1).
>
> That doesn't work:
>
> s.sendto(data, ("ff02::1%net1",port))
> s.sendto(data, ("fe80::2c0:4eff:fe40:5f%net1",port))
>
> The "%net1" appears to be ignored, and the packet will go out _some_
> interface, but I can't figure out how it decides which one (it's not
> always the same one).
The only way I've found is to use socket.getaddrinfo(), which does
accept "%net1" after the IPv6 address, and returns scope_id (actually a
complete sockaddr). I can't access my files now, by I think
socket.getaddrinfo("fe80::2c0:4eff:fe40:5f%net1",port,...)
should work for you (family, socktype etc should be passed also to avoid
searching the results of getaddrinfo()).
Hope this helps,
-- Alain.
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