On 2014-10-22 23:30, Seymore4Head wrote:
On Wed, 22 Oct 2014 16:30:37 -0400, Seymore4Head
<Seymore4Head@Hotmail.invalid> wrote:
One more question.
if y in str(range(10)
Why doesn't that work.
In what way doesn't it work?
If you want to know what it returns, print it out.
I commented it out and just did it "long hand"
def nametonumber(name):
lst=[]
nx=[]
for x in (name):
You don't need to put the parens around name...
lst.append(x)
for y in (lst):
...or around lst.
You're iterating over a string, putting its characters into a list, and
then iterating over that list. You're doing more work than you need to!
#if y in str(range(10)):
if y in "1234567890":
nx.append(y)
if y in " -()":
nx.append(y)
if y in "abc":
nx.append("2")
if y in "def":
nx.append("3")
if y in "ghi":
nx.append("4")
if y in "jkl":
nx.append("5")
if y in "mno":
nx.append("6")
if y in "pqrs":
nx.append("7")
if y in "tuv":
nx.append("8")
if y in "wxyz":
nx.append("9")
number="".join(str(e) for e in nx)
The list nx already contains strings, so you don't need str here.
return (number)
You don't need the parens here either.
a="1-800-getcharter"
print (nametonumber(a))#1800 438 2427 837
a="1-800-leo laporte"
print (nametonumber(a))
a="1 800 callaprogrammer"
print (nametonumber(a))
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