On Wednesday, October 15, 2014 7:35:18 AM UTC+5:30, Dave Angel wrote:
> anurag Wrote in message:
> > I have a dictionary that looks like this:
> > {"1":{"Key1":"Value1", "Key2":"Value2", "Key3":"Value3"},
> > "2":{"Key1":"Value1", "Key2":"Value2", "Key3":"Value3"},
> > "3":{"Key1":"Value1", "Key2":"Value2", "Key3":"Value3"},
> > "4":{"Key1":"Value1", "Key2":"Value2", "Key3":"Value3"}}
> > Now if I have 100 objects like these and I need to split them into 3
> > smaller dicts in a ratio 2:3:5, how could I do that?
> > I tried using numpy.random.choice(), but it says it needs to be a 1-d array.
> What have you actually tried? You haven't shown any actual code.
> Look up the method dict.keys, and see how you might use that. Then
> look up random.shuffle, and see what it would do. Also look up
> dict.sort, since your two messages on this thread imply two
> conflicting goals as to which sub dictionaries should go in which
> of your buckets.
> As for extracting 20% of the keys, slicing is your answer. If
> there are 100 keys, 20, 30, and 50 need to be sliced
> off.
> Then you'll need a loop to build each result dictionary from its keys.
> There are shortcuts, but it's best to learn the fundamentals first.
> Try writing the code. If it doesn't all work show us what you've
> tried, and what you think is wrong. And when you get an
> exception, show the whole traceback, don't just paraphrase one
> of the lines.
Yes that is what is in general expected out here -- code --
maybe working, maybe not, maybe incomplete, maybe 'pseudo' etc
Then others here will improve it
However there is one conceptual thing that perhaps should be mentioned: order.
Is your data *essentially* ordered?
And by 'essentially' I mean you think of it independent of python.
Yeah in python dicts are unordered and lists are ordered and one can fudge
one to behave a bit like the other. But before you fudge, please ponder which
you really need/want.
Below a bit of going from one to other
# dict -> list
>>> d = {"a":1,"b":2,"c":3}
>>> d
{'a': 1, 'c': 3, 'b': 2}
>>> list(d)
['a', 'c', 'b']
# alternate
>>> d.keys()
['a', 'c', 'b']
>>> d.items()
[('a', 1), ('c', 3), ('b', 2)]
>>> d.values()
[1, 3, 2]
# list -> dict
>>> dict(d.items())
{'a': 1, 'c': 3, 'b': 2}
# round-tripping
>>> dict(d.items()) == d
True
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