On Sun, 12 Oct 2014 17:08:00 +0000, Shiva wrote: > while ans.lower() != 'yes' or ans.lower()[0] != 'y':
while ans.lower() is not equal to "yes" or ans.lower()[0] is not equal to "y" the loop will continue to run Note that if ans.lower() == 'y', then the first clause ( ans.lower() != 'yes' ) is true, so the loop will continue to run, ignoring the result of the second clause ( ans.lower()[0] != 'y' ), This will also be the case if you reverse the order of the clauses. It seems that you need a better understanding of combinatorial logic, perhaps http://www.ee.surrey.ac.uk/Projects/Labview/boolalgebra/ index.html#booleantheorems will help. -- Denis McMahon, denismfmcma...@gmail.com -- https://mail.python.org/mailman/listinfo/python-list
