(For future reference, when responding to answers, it's worthwhile to continue to cc python-list.)
On Thu, Oct 9, 2014 at 11:12 AM, Marcos Schratzenstaller < marksabb...@gmail.com> wrote: > The numpy has a function which manipulate 64 bits integers, but I couldn't > find a specific method to multiplicate this kind of objects can not be > manipulated as the same way, so if python is using the correct function > (assuning python is detecting the object, calling the correct function) it > is not a problem, but, where can I find this deep information? Marcos, Yes, the builtin help() function serves as reasonable documentation in this case: >>> help(numpy.int64) Help on class int64 in module numpy: class int64(signedinteger, __builtin__.int) | 64-bit integer. Character code 'l'. Python int compatible. | | Method resolution order: | int64 | signedinteger | integer | number | generic | __builtin__.int | __builtin__.object | | Methods defined here: ... | Methods inherited from generic: | | __abs__(...) | x.__abs__() <==> abs(x) | | __add__(...) | x.__add__(y) <==> x+y ... | __mod__(...) | x.__mod__(y) <==> x%y | | __mul__(...) | x.__mul__(y) <==> x*y ... The __mul__ method implements multiplication. I don't know the specific implementation in numpy, but it's probably little more than a thin wrapper around x * y (with perhaps some type and overflow checking). Skip
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