Seymore4Head wrote: > A little more: decimal_portion > > Write a function that takes two number parameters and returns a float > that is the decimal portion of the result of dividing the first > parameter by the second. (For example, if the parameters are 5 and 2, > the result of 5/2 is 2.5, so the return value would be 0.5) > > http://imgur.com/a0Csi43 > > def decimal_portion(a,b): > return float((b/a)-((b//a))) > > print (decimal_portion(5,2)) > > I get 0.4 and the answer is supposed to be 0.5.
Hint: given arguments a=5, b=2, you want 5/2. What do you calculate? Look at the order of the arguments a and b in the function def line, and in the calculations you perform. Once you fix that, I can suggest a more efficient way of calculating the answer: use the modulo operator % Given arguments 5 and 2, you want 0.5 == 1/2, and 5%2 returns 1. Given arguments 6 and 2, you want 0.0 == 0/2, and 6%2 returns 0. Given arguments 8 and 3, you want 0.6666... == 2/3, and 8%3 returns 2. P.S. the usual name for this function is "fraction part", sometimes "fp". -- Steven -- https://mail.python.org/mailman/listinfo/python-list
