On 9/23/14 4:53 PM, Denis McMahon wrote:
from string import *
You aren't using any names from string, so you can skip this line.
x={'f1':1,'f2':2,'f3':3}
y = [ (a,x[a]) for a in x.keys() ]
y.sort( cmp=lambda a,b: cmp(a[0],b[0]) )
This is more easily done as:
y = sorted(x.items())
.items() returns a sequence of (key, value) pairs, and tuples are sorted
lexicographically, so the first elements are compared first, then the
second, etc.
--
Ned Batchelder, http://nedbatchelder.com
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