On Wednesday, September 17, 2014 6:10:35 PM UTC+3, Chris Angelico wrote:
> On Thu, Sep 18, 2014 at 12:55 AM, cool-RR <ram.rac...@gmail.com> wrote:
> > Terry, that doesn't really answer the question "why", it just pushes it 
> > back to the documentation. Is there a real answer why? Why return NaN when 
> > Inf would make mathematical sense?
> >
> To answer that, we have to first look at what it means to do
> operations on Inf. The definition of "Infinity + 1" is the limit of "x
> + 1" as x goes toward positive infinity - which is positive infinity.
> Same with infinity-1, infinity/1, infinity*1, etc, etc, etc. So far,
> so good. But as x tends toward positive infinity, the value of "x //
> 1" (or simply of floor(x)) doesn't simply increase tidily. It goes up
> in little jumps, every time x reaches a new integer. 

Despite the fact it goes up in jump, it still satisfies the mathematical 
condition needed for a limit. (I won't quote the epsilon-delta thing but I 
think you can find it.) 

> And while it's
> conceivable to define that infinity divided by anything is infinity,
> and infinity modulo anything is zero, that raises serious issues of
> primality and such; 
> I'm not sure that that would really help anything.

I didn't ask for the modulo, I agree it should remain NaN. I'm talking about 
the floor division. I don't see any problems this will cause with primality. 
"I'm not sure that that would really help anything" is a little bit too vague.


Thanks,
Ram.
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