On Tue, Sep 16, 2014 at 6:49 PM, Thomas Rachel <nutznetz-0c1b6768-bfa9-48d5-a470-7603bd3aa...@spamschutz.glglgl.de> wrote: > Am 13.09.2014 09:22 schrieb Chris Angelico: > >> In that case, don't iterate over the list at all. Do something like this: >> >> while lst: >> element = lst.pop(0) >> # work with element >> lst.append(new_element) > > > And if you don't like that, define a > > def iter_pop(lst): > while lst: > yield lst.pop(0) > > and you can do > > for element in iter_pop(lst):
But that's exactly the same thing, with another level of indirection. It certainly isn't the advantage you'd expect from an iterator, namely that it simply stores a marker that gets advanced to the next element. Popping the 0th element is costly, wrapping it into an iterator conceals that. ChrisA -- https://mail.python.org/mailman/listinfo/python-list
