On 2014-08-27 23:42, MRAB wrote: > How many parameters are there? len(self.param) > > Make that many placeholders and then join them together with commas: > > ', '.join(['?'] * len(self.param))
I prefer the clarity of Peter Otten's suggestion of
', '.join('?' * len(self.param))
over the mild obscurity of putting it in a list before multiplying.
-tkc
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