On Mon, 25 Aug 2014 18:22:35 -0400, Terry Reedy <tjre...@udel.edu>
wrote:
>On 8/25/2014 4:14 PM, Seymore4Head wrote:
>> import random
>> sets=3
>> for x in range(0, sets):
>> pb2=random.choice([1-53])
>
>You want random.randint(1, 53)
>...
>> alist = sorted([pb1, pb2, pb3, pb4, pb5])
>> print ("Your numbers: {} Powerball: {}".format(alist, pb6))
>>
>> I am trying this example. The program works, but the numbers don't
>> line up if the number of digits are different sizes.
>> http://openbookproject.net/pybiblio/practice/wilson/powerball.php
>
>To get them to line up, you have to format each one to the same width.
>
>> Suggestion please?
>> BTW the exercise instructions say to use the choice function.
>
>import random
>sets=3
>
>def ran53():
> return random.randint(1, 53)
>
>f1 = '{:2d}'
>bform = "Your numbers: [{0}, {0}, {0}, {0}, {0}]".format(f1)
>pform = " Powerball: {0}".format(f1)
>
>for x in range(0, sets):
> balls = sorted(ran53() for i in range(5))
> print(bform.format(*balls), pform.format(ran53()))
>
I modified your code to only use lotto numbers that don't repeat. I
am sure there is a more elegant way to this too.
import random
sets=10
print ("How many sets of numbers? ",sets)
f1 = '{:2d}'
bform = "Your numbers: [{0}, {0}, {0}, {0}, {0}]".format(f1)
pform = " Powerball: {0}".format(f1)
for x in range(0, sets):
balls = sorted(random.randint(1, 53) for i in range(5))
if balls[0]!= balls[1] and balls[1]!= balls[2] and balls[2]!=
balls[3] and balls[3]!= balls[4]:
print(bform.format(*balls), pform.format(random.randint(1,
42)))
sets=sets-1
Thanks
>> BTW the exercise instructions say to use the choice function.
>
>I am not a fan of exercises that say to do something the wrong way, but
>if you really had to,
>
>n54 = [i for i in range(1, 54)]
>random.choice(n54)
>
>An alternative to choosing numbers is to choose from 2-char number strings.
>
>n53 = ['%2d' % i for i in range(1, 54)]
>
>But then you have to figure out how to avoid having 6 pairs of quotes in
>the output ;=)
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