On Tue, 26 Aug 2014 00:48:52 +0200, Peter Otten <__pete...@web.de>
wrote:
>Terry Reedy wrote:
>
>> On 8/25/2014 4:14 PM, Seymore4Head wrote:
>>> import random
>>> sets=3
>>> for x in range(0, sets):
>>> pb2=random.choice([1-53])
>>
>> You want random.randint(1, 53)
>> ...
>>> alist = sorted([pb1, pb2, pb3, pb4, pb5])
>>> print ("Your numbers: {} Powerball: {}".format(alist, pb6))
>>>
>>> I am trying this example. The program works, but the numbers don't
>>> line up if the number of digits are different sizes.
>>> http://openbookproject.net/pybiblio/practice/wilson/powerball.php
>>
>> To get them to line up, you have to format each one to the same width.
>>
>>> Suggestion please?
>>> BTW the exercise instructions say to use the choice function.
>>
>> import random
>> sets=3
>>
>> def ran53():
>> return random.randint(1, 53)
>>
>> f1 = '{:2d}'
>> bform = "Your numbers: [{0}, {0}, {0}, {0}, {0}]".format(f1)
>> pform = " Powerball: {0}".format(f1)
>>
>> for x in range(0, sets):
>> balls = sorted(ran53() for i in range(5))
>
>Quoting the problem description: "The first five numbers are drawn from a
>drum containing 53 balls"
>
>Thus no number should repeat in the first five. With your approach such
>repetitions can happen. The simplest solution is of course
>
>random.sample(range(1, 54), 5)
>
>but the OP will learn more when he tries to figure out how to get a correct
>solution with choice().
>
Don't bet on it. :)
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