let me paste it again to make my question more clear:
>>>c2.d
__get__() is called <__main__.C2 object at 0x000000000297BE10>
<class '__main__.C2'>
<__main__.C object at 0x000000000297BBA8>
>>> c2.d.a
__get__() is called <__main__.C2 object at 0x000000000297BE10>
<class '__main__.C2'>
__getattribute__() is called
'abc'
Why the result of c2.d.a is not :
__get__() is called <__main__.C2 object at 0x000000000297BE10>
<class __main__.C2'>
<__main__.C object at 0x000000000297BBA8>
__getattribute__() is called
'abc'
Why the` return self` in the __get__ method in class C does not work?
Why there is no <__main__.C object at 0x000000000297BBA8> in the output?
and the source code are:
|class C(object):
a = 'abc'
def __getattribute__(self, *args, **kwargs):
print("__getattribute__() is called")
return object.__getattribute__(self, *args, **kwargs)
def __getattr__(self, name):
print("__getattr__() is called ")
return name + " from getattr"
def __get__(self, instance, owner):
print("__get__() is called", instance, owner)
return self
def foo(self, x):
print(x)
class C2(object):
d = C()
|
On 8/23/2014 12:10 PM, Ian Kelly wrote:
On Thu, Aug 21, 2014 at 7:25 PM, luofeiyu <elearn2...@gmail.com
<mailto:elearn2...@gmail.com>> wrote:
> >>> c2.d.a
> __get__() is called <__main__.C2 object at 0x000000000297BE10>
<class '__main__.
> C2'>
> __getattribute__() is called
> 'abc'
>
> Why the result of c2.d.a is not :
>
> __get__() is called <__main__.C2 object at 0x000000000297BE10>
<class '__main__.
> C2'>
> __getattribute__() is called
> 'abc'
As far as I can tell you pasted the same output twice, so I don't
understand what it is that you're asking.
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