Chris 

Thank you for the info.  I figure it out. But thank you again.

Ed 
> On Jul 28, 2014, at 5:42 PM, Chris Kaynor <ckay...@zindagigames.com> wrote:
> 
> On Mon, Jul 28, 2014 at 2:33 PM, Edward Manning <ejmmann...@gmail.com> wrote:
> I wrote this code, but it seem to work fine if I only have one ip in the 
> file. When I have more than one IP in the file 
> I get a error. Does anyone have an idea why.    
> 
> It would be helpful to know what the error you are getting is. It is also a 
> good idea to generally provide the Python version and OS version with your 
> messages, as they can often make a major difference. As it is, I've made my 
> best guess below (in bold), I've also included some other notes that may 
> cause issues, but I doubt are causing your error.
>  
> import socket
>  
>  
> def main():
>  
>     # get file names
>     infileName = input ("What file our the IP adderss in?  ")
>     outfileName = input("What file should the results go in?")
>  
>     # open files
>     infile = open(infileName, "r")
>     outfile = open(outfileName, "w")
> 
> While this shouldn't cause the issue your reporting (without other issues 
> going on), Its generally a better idea to use the with statement to open 
> file, like so:
> with open(infileName, "r") as infile:
>     # code that needs infile goes here.
> 
> This will ensure that the file is closed when you are done with it, even if 
> an error occurs in the code that may prevent the code from running to 
> completion.
>  
>  
>  
>     #Proccess each line of the input file
>  
>     for line in infile:
>         ipAddress = line.strip()
> 
> I'm guessing that, when you only have one IP, you do not have a trailing 
> new-line in the file, but when you put more than one in the file, you have a 
> trailing new-line. You can try adding:
> 
> if not ipAddress:
>     continue
> 
> here to ignore any empty lines (due to the line.strip() above, it will also 
> ignore all white-space lines) you might get. This may be the cause of your 
> error...
>  
>         resluts = socket.gethostbyaddr(ipAddress)
>         print(resluts[0],resluts[2], end="")
> 
> Note that this does not seem to be printing into outfile (its printing to 
> stdout instead). I presume this is for debugging purposes.
>  
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