On Thu, Jun 26, 2014 at 9:24 PM, Chris Angelico <ros...@gmail.com> wrote: > But you're right that this can be very surprising. And it's inherent > to the concept of digits having more range than just "high" or "low", > so there's no way you can get this with binary floats.
For an average of two numbers, I think that's true. For an average of more than two numbers, it's possible. >>> a = 2.0 ** 53 - 1 >>> b = 2.0 ** 53 - 2 >>> a 9007199254740991.0 >>> b 9007199254740990.0 >>> (a + b + b) / 3 9007199254740989.0 -- https://mail.python.org/mailman/listinfo/python-list
