On Fri, May 9, 2014 at 7:13 PM, Stefan Behnel <stefan...@behnel.de> wrote: > Chris Angelico, 09.05.2014 11:02: >> On Fri, May 9, 2014 at 6:59 PM, Percy Tambunan wrote: >>> Hai, I would like to parse this multiple root element XML >> >> Easy fix might be to wrap it in <root> and </root>, which will give >> you a new root. > > ElementTree's XMLParser() can be use efficiently for this. Something like > this should work: > > from xml.etree.ElementTree import XMLParser > > parser = XMLParser() > parser.feed(b'<root>') > parser.feed(real_input_data) > parser.feed(b'</root>') > root = parser.close() > > for subtree in root: > ...
That looks good to me :) ChrisA -- https://mail.python.org/mailman/listinfo/python-list
