Maybe something like this? >>> to_num = lambda array: np.sum(array * 2**np.arange(len(array)-1, -1, -1)) >>> to_num(np.array([1,0,1,0])) 10
2014-04-29 17:42 GMT+02:00 Tom P <werot...@freent.dd>: > On 28.04.2014 15:04, mboyd02...@gmail.com wrote: > >> I have a numpy array consisting of 1s and zeros for representing binary >> numbers: >> >> e.g. >> >> >>> binary >> array([ 1., 0., 1., 0.]) >> >> I wish the array to be in the form 1010, so it can be manipulated. >> >> I do not want to use built in binary converters as I am trying to build >> my own. >> >> > Do you mean that each element in the array represents a power of two? > So array([ 1., 0., 1., 0.]) represents 2^3 + 2 = 6 decimal? > > -- > https://mail.python.org/mailman/listinfo/python-list >
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