On 2014-04-15, Dave Angel <da...@davea.name> wrote:
> Your variable 'size' is declared as size_t, which is an integer
> the size of a pointer.
While that may always be true in practice (at least with gcc), I don't
think the C standard requires it. size_t is guaranteed to be unsigned
with at least 16 bits and sufficiently wide to represent the size of
any object. It might be possible, in theory, to have an architecture
that used 64-bit pointers but restricted each data space to 32-bits
and therefore could use 32-bit values for size_t.
If you want to declare an integer the size of a pointer, then the
choices are intptr_t (signed), uintptr_t (unsigned), and ptrdiff_t
(signed value representing the difference between to pointers).
> Not necessarily the same as an int.
Indeed.
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