On 2014-04-03 19:10, dave em wrote:
> So my first step is to compute the key. I suspect my error below
> is because c1 is a float and m1 is a string but I don't know how to
> turn the string into a float.
For the record, "c1" in your example should be an integer/long
It sounds like you want the optional parameter to int() so you'd do
>>> hex_string = "My text message".encode("hex")
>>> hex_string
'4d792074657874206d657373616765'
>>> m1 = int(hex_string, 16) # magic happens here
>>> m1
402263600993355509170946582822086501L
>>> c1=0x6c73d5240a948c86981bc294814d
>>> c1
2199677439761906166135512011931981L
>>> k = m1 ^ c1
>>> k
400239414552556350237329405469124136L
>>> hex(k) # as a string
'0x4d1553a14172e0acebfd68b1f5e628L'
-tkc
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