On Mon, Mar 17, 2014 at 11:40 AM, Chris Angelico <ros...@gmail.com> wrote:
> Antoine says that this doesn't even stop the thread
> (I can't say; I've never used _stop(), for obvious reasons), so this
> code was doubly broken.
I was curious about that -- after all, Python's threads aren't truly
concurrent, so perhaps they could just test the flag each time they
resume -- so I tested it using 3.3. First I tried simply adding a
print call on to the end of the OP's function:
>>> def stale():
... import time
... time.sleep(1000)
... print('hello')
...
>>> t = threading.Thread(target=stale)
>>> t.start(); t._stop()
No output was printed, so at least a sleeping thread can apparently be
stopped. Then I tried removing the sleep call:
>>> def stale():
... for i in range(10): print('hello')
...
>>> t = threading.Thread(target=stale)
>>> t.start(); print('Starting'); t._stop(); print('Stopping')
hello
Starting
Stopping
>>> hello
hello
hello
hello
hello
hello
hello
hello
hello
So yes, despite the lack of true concurrency, a thread can continue to
run after its _stop has been called.
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