On Tuesday, February 11, 2014 2:24:01 AM UTC-5, cas...@gmail.com wrote: > On Monday, February 10, 2014 6:40:03 PM UTC-8, hlauk.h...@gmail.com wrote: > > > I am coming off Python 2.6.6 32 bite platform and now in win 8.1 64 bite. > > > I had no problems with gmpy in 2.6.6 and large integer floating points where > > > you could control the length of the floating point by entering the bite size > > > of the divisor(s) you are using. That would give the limit length of the > > float > > > in the correct number of bites. > > > > > > In Python 3.3.3 and gmpy2 I have tried many things in the import mpfr module > > > changing and trying all kinds of parameters in the gmpy2 set_context module > > > and others. > > > > > > The best I can get without an error is the results of a large integer > > > division is a/b = inf. or an integer rounded up or down. > > > I can't seem to find the right settings for the limit of the remainders in > > the > > > quotient. > > > > > > My old code in the first few lines of 2.6.6 worked great and looked like > > this - > > > > > > import gmpy > > > > > > BIG =(A large composite with 2048 bites) > > > SML =(a smaller divisor with 1024 bites) > > > > > > Y= gmpy.mpz(1) > > > A= gmpy.mpf(1) > > > > > > y=Y > > > > > > x=BIG > > > z=SML > > > a=A > > > k=BIG > > > j=BIG > > > x=+ gmpy.next.prime(x) > > > > > > while y < 20: > > > B = gmpy.mpf(x.1024) > > > ## the above set the limit of z/b float (see below) to 1024 > > > b=B > > > a=z/b > > > c=int(a) > > > d=a-c > > > if d = <.00000000000000000000000000000000001: > > > proc. continues from here with desired results. > > > > > > gmpy2 seems a lot more complex but I am sure there is a work around. > > > I am not interested in the mod function. > > > > > > My new conversion proc. is full of ## tags on the different things > > > I tried that didn't work. > > > > > > TIA > > > Dan > > > > The following example will divide two integers with a result precision > > of 1024 bits: > > > > import gmpy2 > > > > # Set mpfr precision to 1024 > > gmpy2.get_context().precision=1024 > > > > # Omitting code.... > > > > a = gmpy2.mpz(SML)/gmpy2.mpz(x) > > > > Python 3.x performs true division by default. When integer division involves > > an mpz, the result will be an mpfr with the precision of the current context. > > > > Does this help? > > > > casevh
Thanks a lot, I will give it a go. Dan -- https://mail.python.org/mailman/listinfo/python-list
