On 1/25/14 1:37 AM, seasp...@gmail.com wrote:
take the following as an example, which could work well.
But my concern is, will list 'l' be deconstructed after function return? and
then iterator point to nowhere?
def test():
l = [1, 2, 3, 4, 5, 6, 7, 8]
return iter(l)
def main():
for i in test():
print(i)
One more thing: there's no need to call iter() explicitly here. Much
more common than returning an iterator from a function is to return an
iterable. Your code will work exactly the same if you just remove the
iter() call:
def test():
l = [1, 2, 3, 4, 5, 6, 7, 8]
return l
def main():
for i in test():
print(i)
--
Ned Batchelder, http://nedbatchelder.com
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