Try that, it may not be the better solution, but it seems to work:
#def invertDict(d):
# d2 = {}
# for k, v in d.iteritems():
# d2.setdefault(v, []).append(k)
# return d2
Cyril
On 7/11/05, Ric Da Force <[EMAIL PROTECTED]> wrote:
Hi all,
I have a dictionary containing about 300 items, some of the values being
repeated. Both keys and values are strings. How can I turn this thing on
its head so that we create a key based on each unique value and build the
values based on the keys corresponding to the repeated values?
It is hard to explain but this is what I mean:
Dict = {'rt': 'This is repeated', 'sr': 'This is repeated', 'gf': 'This is
not'}
I want this to return a new dict with string keys and lists containing the
previous keys for repeated values.
NewDict = {'This is repeated':['rt','sr'],'This is not':['gf']}
I am still learning Python and have struggled with this for hours before
deciding to go for help. Unfortunately, I didn't really know how to search
for this in google and decided to post it here. I apologise if this is too
basic for this newsgroup...
Ric
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