On 1/10/2014 12:38 PM, Albert-Jan Roskam wrote:
In Python Cookbook, one of the authors (I forgot who) consistently used the "L[:]" idiom like below. If the second line
simply starts with "L =" (so no "[:]") only the name "L" would be rebound, not the underlying
object. That was the authorś explanation as far as I can remember. I do not get that. Why is the "L[:]" idiom more
memory-efficient here? How could the increased efficiency be demonstrated?
#Python 2.7.3 (default, Sep 26 2013, 16:38:10) [GCC 4.7.2] on linux2
L = [x ** 2 for x in range(10)]
L[:] = ["foo_" + str(x) for x in L]
Unless L is aliased, this is silly code. The list comp makes a new list
object, so if L does not have aliases, it would be best to rebind 'L' to
the existing list object instead of copying it. To do the replacement
'in place':
L = [x ** 2 for x in range(10)]
for i, n in enumerate(L):
L[i] = "foo_" + str(n)
print(L)
>>>
['foo_0', 'foo_1', 'foo_4', 'foo_9', 'foo_16', 'foo_25', 'foo_36',
'foo_49', 'foo_64', 'foo_81']
--
Terry Jan Reedy
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