On 12/22/2013 04:55 PM, Dan Healy wrote:
Overview: I'm attempting to read strings from a serial port. Each string ends
with a carriage return and line feed. I want to write those strings to a file,
like a log file. So, if I send P1 and the P2 on a new line, I would expect to
open this file and find (line 1) P1 (line 2) P2.
Problem: The file only contains P2. It always overwrites the first line. I can
send 20 strings and the file will always contain the last string received.
Code:
#Import the serial module
import serial
#Open the serial port w/ settings
ser=serial.Serial(
port="/dev/ttyUSB0",
baudrate=9600,
timeout=None)
#Print data received on the serial port after removing the CR and LF characters
while True:
rawcode=ser.readline()
codelog=open('/home/pi/avdms/codes.log','w')
codelog.write(rawcode)
codelog.close()
First, that code is quite foolish: If you want to write multiple lines
to a file, open the file once before the loop, looped through all your
writes, and then closed it after the loop has exited.:
codelog=open('/home/pi/avdms/codes.log','w')
while True:
rawcode=ser.readline()
codelog.write(rawcode)
codelog.close()
However, on the chance that you are writing this code for testing
purposes, and you really do have a need to open a file, write something
onto the end and then close the file, and that you are going to do this
many times, I'll continue with this response:
The default behavior of the "open" call is to *truncate* (i.e.,
clear the contents) and start writing at the beginning. The
behavior you want is called *append*, and you get it with a 'wa' as
the second parameter of the open call.
See http://docs.python.org/3/library/functions.html#open for a list of
other modes available for the open call.
Gary Herron
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