On Monday, December 16, 2013 7:29:31 AM UTC+5:30, alex23 wrote:
> > # Need to compare values of counter and reject in function/routine in value 
> > in counter2 is higher then value in counter1 for a current key

>      [(k,Counter2[k]) for k in Counter2 - Counter1]

Why not just?

Counter2 - Counter1

And if you want to uncounterify it then
dict(Counter2 - Counter1)

> Counters are awesome.

Yes -- agreed. But 'counter' is a strange name -- after checking whether
'bag' and 'multiset' are there in the library, I would not think to
check anything else.
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