Helmut Jarausch wrote:
> Hi,
>
> I'd like to extracted elements from a heapq in a for loop.
> I feel my solution below is much too complicated.
> How to do it more elegantly?
> I know I could use a while loop but I don't like it.
>
> Many thanks for some lessons in Python.
>
> Here is my clumsy solution
>
> from heapq import heappush, heappop
> # heappop raises IndexError if heap is empty
>
> H=[]
> for N in 'H','C','W','I' :
> heappush(H,N)
H = ["H", "C", "W", "I"]
heapq.heapify(H)
But see below.
> # how to avoid / simplify the following function
>
> def in_sequence(H) :
> try :
> while True :
> N= heappop(H)
> yield N
> except IndexError :
> raise StopIteration
>
> # and here the application:
>
> for N in in_sequence(H) :
> print(N)
If you are iterating over the complete heap I see no advantage over a sorted
list. So
for N in sorted(H):
print(N)
If H is huge use H.sort() instead of sorted() to save memory.
If you need only a few items use heapq.nsmallest().
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