On Sun, Nov 24, 2013 at 3:30 AM, Antoon Pardon <antoon.par...@rece.vub.ac.be> wrote: > Op 23-11-13 22:51, Peter Otten schreef: >> Antoon Pardon wrote: >> >>> Op 23-11-13 10:01, Peter Otten schreef: >>> >>>> >>>> Your script is saying that a staticmethod instance is not a callable >>>> object. It need not be because >>>> >>>> Foo.foo() >>>> >>>> doesn't call the Foo.foo attribute directly, it calls >>>> >>>> Foo.foo.__get__(None, Foo)() >>> >>> I think you are burdening the programmer with implemantation details >>> that don't matter to him. >>> >>> IMO if Foo.foo() is legal then Foo.foo is callable. That the actual call >>> is delegated to Foo.foo.__get__(None, Foo) shouldn't matter. >> >> If you read the original post -- I think in this case the details do matter. >> >> What is your highlevel explanation for > > I don't care about what kind of explanation. I care about a correct answer to > the question whether a particular object is callable (from a programmers point > of view). I'm sure you can give a very comprehensive explanation for why in > this case we get an incorrect answer but that doesn't make the behaviour > correct. > > Foo.foo() is legal here. So Foo.foo is callable. So you starting with it > needn't > be callable is using "callable" with a different meaning than the natural > interpretation. Al the rest is just an attempt in getting others to accept > your > use of "callable" instead of the natural one. > > Foo.foo() being legal and Foo.foo not being callable is IMO a bug in python. > No matter > what explanation you have for the behaviour.
Your supposition that Foo.foo is not considered callable by Python is false, as Chris already demonstrated, and I don't see where anybody here has stated otherwise. What Peter wrote was that "a staticmethod instance is not a callable object", which is absolutely correct, and these two facts are consistent because Foo.foo is not a staticmethod instance (Foo.__dict__['foo'] on the other hand *is* a staticmethod instance and *is not* callable, and Foo.__dict__['foo']() will correspondingly raise a TypeError). -- https://mail.python.org/mailman/listinfo/python-list
