Re: compare two list of dictionaries

Tobiah Fri, 04 Oct 2013 12:37:26 -0700

On 10/03/2013 09:11 AM, Mohan L wrote:

Dear All,


I have two list of dictionaries like below:

In the below dictionaries the value of ip can be either hostname or ip address.

output1=[
{'count': 3 , 'ip': 'xxx.xx.xxx.1'},
{'count': 4, 'ip': 'xxx.xx.xxx.2'},
{'count': 8, 'ip': 'xxx.xx.xxx.3'},
{'count': 10, 'ip': 'xxx.xx.xxx.4'},
{'count': 212, 'ip': 'hostname1'},
{'count': 27, 'ip': 'hostname2'},
{'count': 513, 'ip': 'hostname3'},
{'count': 98, 'ip': 'hostname4'},
{'count': 1, 'ip': 'hostname10'},
{'count': 2, 'ip': 'hostname8'},
{'count': 3, 'ip': 'xxx.xx.xxx.11'},
{'count': 90, 'ip': 'xxx.xx.xxx.12'},
{'count': 12, 'ip': 'xxx.xx.xxx.13'},
{'count': 21, 'ip': 'xxx.xx.xxx.14'},
{'count': 54, 'ip': 'xxx.xx.xxx.15'},
{'count': 34, 'ip': 'xxx.xx.xxx.16'},
{'count': 11, 'ip': 'xxx.xx.xxx.17'},
{'count': 2, 'ip': 'xxx.xx.xxx.18'},
{'count': 19, 'ip': 'xxx.xx.xxx.19'},
{'count': 21, 'ip': 'xxx.xx.xxx.20'},
{'count': 25, 'ip': 'xxx.xx.xxx.21'},
{'count': 31, 'ip': 'xxx.xx.xxx.22'},
{'count': 43, 'ip': 'xxx.xx.xxx.23'},
{'count': 46, 'ip': 'xxx.xx.xxx.24'},
{'count': 80, 'ip': 'xxx.xx.xxx.25'},
{'count': 91, 'ip': 'xxx.xx.xxx.26'},
{'count': 90, 'ip': 'xxx.xx.xxx.27'},
{'count': 10, 'ip': 'xxx.xx.xxx.28'},
{'count': 3, 'ip': 'xxx.xx.xxx.29'}]


In the below dictionaries have either hostname or ip or both.

output2=(

{'hostname': 'INNCHN01', 'ip_addr': 'xxx.xx.xxx.11'},
{'hostname': 'HYDRHC02', 'ip_addr': 'xxx.xx.xxx.12'},
{'hostname': 'INNCHN03', 'ip_addr': 'xxx.xx.xxx.13'},
{'hostname': 'MUMRHC01', 'ip_addr': 'xxx.xx.xxx.14'},
{'hostname': 'n/a', 'ip_addr': 'xxx.xx.xxx.15'},
{'hostname': 'INNCHN05', 'ip_addr': 'xxx.xx.xxx.16'},
{'hostname': 'hostname1', 'ip_addr': 'n/a'},
{'hostname': 'hostname2', 'ip_addr': 'n/a'},
{'hostname': 'hostname10', 'ip_addr': ''},
{'hostname': 'hostname8', 'ip_addr': ''},
{'hostname': 'hostname200', 'ip_addr': 'xxx.xx.xxx.200'},
{'hostname': 'hostname300', 'ip_addr': 'xxx.xx.xxx.400'},

)

trying to get the following difference from the above dictionary

1). compare the value of 'ip' in output1 dictionary with either 'hostname' and 
'ip_addr' output2 dictionary and print their
intersection. Tried below code:


for doc in output1:
         for row in output2:
                 if((row["hostname"] == doc["ip"]) or (row["ip_addr"] == 
doc["ip"])):
                         print doc["ip"],doc["count"]

*output:*
hostname1 212
hostname2 27
hostname10 1
hostname8 2
xxx.xx.xxx.11 3
xxx.xx.xxx.12 90
xxx.xx.xxx.13 12
xxx.xx.xxx.14 21
xxx.xx.xxx.15 54
xxx.xx.xxx.16 34

2). need to print the below output if the value of 'ip' in output1 dictionary 
is not there in in output2 dictionary(ip/hostname
which is there in output1 and not there in output2):

  xxx.xx.xxx.1 3
  xxx.xx.xxx.2 4
  xxx.xx.xxx.3  8
  xxx.xx.xxx.4  10
  hostname3  513
  hostname4  98
  xxx.xx.xxx.17  11
  xxx.xx.xxx.18  2
  xxx.xx.xxx.19  19
  xxx.xx.xxx.20  21
  xxx.xx.xxx.21  25
  xxx.xx.xxx.22  31
  xxx.xx.xxx.23  43
  xxx.xx.xxx.24  46
  xxx.xx.xxx.25  80
  xxx.xx.xxx.26  91
  xxx.xx.xxx.27  90
  xxx.xx.xxx.28  10
  xxx.xx.xxx.29  3

3). Ip address with is there only in output2 dictionary.

xxx.xx.xxx.200
xxx.xx.xxx.400

Any help would be really appreciated. Thank you

Thanks
Mohan L


There is a bit of work that can be consolidated
to help both case 2 and 3.  Then both cases are
a little more straightforward:

##################################################

import itertools

inside_out = {x['ip']: x for x in output1}

set1 = set(inside_out.keys())

### CASE 2 ###
set2 = set(itertools.chain.from_iterable([x.values() for x in output2]))
for name in set1 - set2:
        print name, inside_out[name]['count']


### CASE 3 ###
set2 = set([x['ip_addr'] for x in output2])
print "\n".join(set2 - set1)


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