Anthony Papillion wrote: > Hello Again Everyone, > > I'm still working to get my head around JSON and I thought I'd done so > until I ran into this bit of trouble. I'm trying to work with the > CoinBase API. If I type this into my browser: > > https://coinbase.com/api/v1/prices/buy > > I get the following JSON returned > > {"subtotal":{"amount":"128.00","currency":"USD"},"fees":[{"coinbase": {"amount":"1.28","currency":"USD"}},{"bank": {"amount":"0.15","currency":"USD"}}],"total": {"amount":"129.43","currency":"USD"},"amount":"129.43","currency":"USD"} > > So far, so good. Now, I want to simply print out that bit of JSON (just > to know I've got it) and I try to use the following code: > > returnedJSON = json.loads('https://coinbase.com/api/v1/prices/buy') > print returnedString > > And I get a traceback that says: No JSON object could be decoded. The > specific traceback is: > > Traceback (most recent call last): > File "coinbase_bot.py", line 31, in <module> > getCurrentBitcoinPrice() > File "coinbase_bot.py", line 28, in getCurrentBitcoinPrice > returnedString = json.loads(BASE_API_URL + '/prices/buy') > File "/usr/lib/python2.7/json/__init__.py", line 326, in loads > return _default_decoder.decode(s) > File "/usr/lib/python2.7/json/decoder.py", line 366, in decode > obj, end = self.raw_decode(s, idx=_w(s, 0).end()) > File "/usr/lib/python2.7/json/decoder.py", line 384, in raw_decode > raise ValueError("No JSON object could be decoded") > ValueError: No JSON object could be decoded > > > I'm very confused since the URL is obviously returned a JSON string. Can > anyone help me figure this out? What am I doing wrong?
Let's see: >>> help(json.loads) Help on function loads in module json: loads(s, encoding=None, cls=None, object_hook=None, parse_float=None, parse_int=None, parse_constant=None, object_pairs_hook=None, **kw) Deserialize ``s`` (a ``str`` or ``unicode`` instance containing a JSON document) to a Python object. [...] So json.loads() expects its first argument to b valid json, no a URL. You have to retrieve the data using other means before you can deserialize it: data = urllib2.urlopen(...).read() returned_json = json.loads(data) Replacing ... with something that works is left as an exercise. (It seems that you have to use a Request object rather than a URL, and that the default "Python-urllib/2.7" is not an acceptable user agent. -- https://mail.python.org/mailman/listinfo/python-list