On Sat, Aug 31, 2013 at 11:33 PM, candide <candide@free.invalid> wrote:
> The if instruction imposes useless testing (we know in advance the problem
> to occur at the very end of the loop) and useless writing (writing '').
>
> The following is clearer
>
> # -------------------------
> n=5
> for i in range(n-1):
> print(i, end=' ')
> print(n-1)
> # -------------------------
>
>
> but doesn't solve all the cases (imagine a string or an iterator).
Similar but maybe simpler, and copes with more arbitrary iterables:
it=iter(range(5))
print(next(it), end='')
for i in it:
print('',i, end='')
Also guarantees to use 'sep' between the elements, fwiw.
ChrisA
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