On Sat, Aug 24, 2013 at 1:37 AM, Ian Kelly <ian.g.ke...@gmail.com> wrote: > > I time this function at about 33% faster than your version for a > six-digit decimal, and almost 50% faster for a 12-digit decimal. My > guess would be because it's not calling str() on every individual > digit. > > def convert(d): > exp = d.as_tuple().exponent > num = int(d.scaleb(-exp)) > return num, 10**-exp
Although, you would need to be careful with handling the decimal context for the scaleb operation to make sure the result is exact. -- http://mail.python.org/mailman/listinfo/python-list
