On Wed, Jul 24, 2013 at 8:34 AM, Rafael Durán Castañeda <rafadurancastan...@gmail.com> wrote: > In [3]: [ y for y in itertools.chain.from_iterable(x)] > Out[3]: ['A0', 'A1', 'A2', 'B0', 'B1', 'B2', 'C0', 'C1', 'C2']
Complete aside, given that this has already been pointed out as solving a different problem: Any time you see a list comp that just does "[ x for x in foo ]", check to see if it can be replaced by a simple list constructor: >>> [ y for y in itertools.chain.from_iterable(x)] ['A0', 'A1', 'A2', 'B0', 'B1', 'B2', 'C0', 'C1', 'C2'] >>> list(itertools.chain.from_iterable(x)) ['A0', 'A1', 'A2', 'B0', 'B1', 'B2', 'C0', 'C1', 'C2'] A bit simpler and achieves the same. ChrisA -- http://mail.python.org/mailman/listinfo/python-list
