> Yeah, it's remarkably easy too! Try this: > > [(k, x) for k, v in my_dict.items() for x in v or [None]] > > An empty list counts as false, so the 'or' will then take the second option, > and iterate over the one-item list with > > None in it.
Right, I overlooked that! Much appreciated, jlc -- http://mail.python.org/mailman/listinfo/python-list
