On 07/09/2013 06:01 PM, Russel Walker wrote:
Sorry for the vague title. Probably best to just show you the code that
explains it better.
This is a simplified example of what I want to do:
# THIS DOESN'T WORK
from random import choice
class Expr(object):
"""
Expr(expr, op, val) -> an expression object.
"""
def __init__(self, expr, op='', val=''):
self.expr = expr # can be another instance of Expression.
self.op = op
self.val = val
def __str__(self):
return ("%s %s %s" % (self.expr, self.op, self.val)).strip()
def expand(self):
self = Expr(self, choice('+-*/'), choice('12345'))
Then I tried messing around with Expr.__new__() and Expr.__init__() but that
didn't work.
The only way I've got it to work is by doing the expanding part outside of the
object, by a method of some other class. But I want the Expr class to be
responsible for itself. How can I do this and why doesn't the above work?
That line in method expand() indicates that you have a fundamental
misunderstanding of the way that names and objects interact in Python.
Names are bound to objects by the assignment operator, but the object
itself is not changed. If you want to change the object that self is
bound to, then change it by mutating it.
You don't change an existing object by binding a name to a new object,
whether of the same or different type. The original object remains
unchanged. The fact that the name is 'self' is totally irrelevant.
a = 45
b = a
a = 12
This does NOT change b.
No idea what you really wanted, but perhaps it's something like:
def expand(self):
self.op = choice("+-*/")
self.val = choice("12345")
No idea what expr is supposed to represent, so I didn't try to
manipulate it here.
--
DaveA
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