On 14/6/2013 5:49 μμ, Grant Edwards wrote:
On 2013-06-14, Nick the Gr33k <supp...@superhost.gr> wrote:
I started another thread
no kidding.
because the last one was !@#$'ed up by irrelevant replies and was
difficult to jeep track.
name="abcd"
month="efgh"
year="ijkl"
print(name or month or year)
abcd
Can understand that, it takes the first string out of the 3 strings
that has a truthy value.
Yes, it does. That's the way the language is defined to work. If you
don't like it, pick a different language.
I can understand OR stops at the first value when it finds it truthy,
and doesn't care for the other expr parameters.
And that logical since we say:
(name or month or year)
is like saying:
print whatever of those 3 are True, at least 1 of them, if it doesn't
not find any though for some reason it defaults to the last variable of
the expression(another mystery for me)
the way i realize it is just that for this boolean evaluation of the
expression to result in True if any of the above vars holds a truthy value.
Nice try, moving me to another newsgroup list :)
print("k" in (name and month and year))
True
No clue. since the expression in parenthesis returns 'abcd'
No it doesn't. Try it:
Python 2.7.3 (default, Mar 20 2013, 14:16:24)
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
name="abcd"
month="efgh"
year="ijkl"
"k" in (name and month and year)
True
(name and month and year)
'ijkl'
how can 'k' contained within 'abcd' ?
Um sorry was a typo.
I mean the expr eval results in the value of var year which is 'ijkl'.
>>>> "k" in (name and month and year)
> True
So yes it does.
My question is why the expr (name and month and year) result in the
value of the last variable whic is variable year?
I cannot understand AND.
Isn't it like saying that:
(name and month and year)
all of these variables have to have truthy values so for the boolaean
eval of the expr result in True?
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What is now proved was at first only imagined!
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