On May 6, 10:59 am, Bradley Wright <bradley.wright....@gmail.com> wrote: > def fizz_cout(x): > count = 0 > for item in x: > while item == "fizz": > count += 1 > return count > > Please remember that i am a eager beginner, where am i going wrong?
There are several problems with your code: > for item in x: > while item == "fizz": > count += 1 The `for` takes an item out of the list `x`. If that item is the string 'fizz', it increments count. As it's a `while` loop, it will continue to increment for as long as `item` is 'fizz'. Since the while loop doesn't look up another list item, it will remain as 'fizz' until the end of time. Well, it would except for your second bug: > while item == "fizz": > count += 1 > return count The very first time it encounters a list item that is 'fizz', it adds one to `count`, then exits the function passing back `count`. You want to move the return to _outside_ the for loop, and you want to change your `while` condition to an `if` instead. -- http://mail.python.org/mailman/listinfo/python-list
