Maybe import mylogger.mylogger as gLog? I don't know what you mean by
"missing a trick". Your example seems pretty pythonic to me, except for the
fact that you use a singleton where you could have a couple of functions
and use the module as the namespace.
On 24 Apr 2013 17:58, "The Night Tripper" <jkn...@nicorp.co.uk> wrote:
> Hi all
> I have a small suite of python modules, say
>
> A.py
> B.py
> C.py
>
> which can be invoked in a variety of ways. eg.
>
> 1) A.py is invoked directly; this imports and uses B.py and C.py
>
> 2) B.py is invoked; this imports and uses A.py and C.py
>
> I use the logging module in all of these python modules, and I want to be
> able to use a single logger across the entire suite of whichever set of
> scripts is running.
>
> The way I do this at the moment is to have a separate module mylogger.py:
>
> == mylogger.py ==
>
> import logging
>
> class MyLogger: #using python 2.4 ;-o
> def __init__(self):
> self.log = logging.getLogger(MY_APP_NAME)
> def setupLogging(self):
> self.log.setlevel(logging.DEBUG)
> # ...
>
> # our singleton logging object
> mylogger = Mylogger()
> # EOF
>
> and then in my other modules A.py, B.py etc. I have something like:
>
> == A.py ==
>
> import mylogger
> gLog = mylogger.mylogger
>
> if __name__ == "__main__":
> gLog.setupLogging()
> gLog.info("Module A running as main")
> main()
> #EOF
>
> == B.py ==
>
> import mylogger
> gLog = mylogger.mylogger
>
> if __name__ == "__main__":
> gLog.setupLogging()
> gLog.info("Module B running as main")
> main()
> # EOF
>
> This works, but I can't help thinking I'm missing a trick here. Any
> suggestions?
>
> Thanks
> j^n
>
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>
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