Thanks Gary.
> > Be clearer about the problem please. > > Do you wish to produce a loop that: > On pass 1, each of p,k, and t hold the first item of their respective > lists, and > on pass 2, each of p,k, and t hold the second item of their respective > lists, and > so on > until one (or all) lists run out? > Yes this is excatly what I want each loop holds the first item on each pass. > > If that is what you want, then check out the zip builtin function. But > also consider this: Do you care what happens if one list runs out before > the others? > Yes, but all dictionaries have same number of items. > > Or is it something else you want? Perhaps nested loops? > for p in sorted(segments.iterkeys()): > for k in sorted(class_count.iterkeys()): > for j in sorted(pixel_count.iterkeys()): > # This will be run with all possible combinations of p,k, and > t > No, I know about nested loops but I dont want that because all the loops have same number of items, inner loops will run out earlier. > > Gary Herron > > > > > > -- > http://mail.python.org/mailman/listinfo/python-list > >
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