On Tue, Apr 9, 2013 at 1:37 AM, Roy Smith <r...@panix.com> wrote: > I can't help point out, however, that if your initial implementation is to > have your code return a constant, it's pretty likely to be an optimum > solution in both time and space :-)
Likely, but not certain. # 1 def fifty_stars(): return "**************************************************" # 2 fifty_stars=lambda "*"*50 Okay, that's just getting 2AM stupid now. :) ChrisA -- http://mail.python.org/mailman/listinfo/python-list