Until now, I was quite sure that the is operator acts the same as the id builtin function, or, to be more formal, that o1 is o2 to be exactly equivalent to id(o1) == id(o2). This equivalence is reported in many books, for instance Martelli's Python in a Nutshell.
But with the following code, I'm not still sure the equivalence above is correct. Here's the code : #-------------------------------------------------------- class A(object): def f(self): print "A" a=A() print id(A.f) == id(a.f), A.f is a.f #-------------------------------------------------------- outputing: True False So, could someone please explain what exactly the is operator returns ? The official doc says : The ‘is‘ operator compares the identity of two objects; the id() function returns an integer representing its identity (currently implemented as its address). -- http://mail.python.org/mailman/listinfo/python-list