On 2013-03-29, Alain Ketterlin <al...@dpt-info.u-strasbg.fr> wrote:
> Victor Hooi <victorh...@gmail.com> writes:
>
>> expression1 = re.compile(r'....')
>> expression2 = re.compile(r'....')
> [...]
>
> Just a quick remark: regular expressions are pretty powerful at
> representing alternatives. You could just stick everything
> inside a single re, as in '...|...'
>
> Then use the returned match to check which alternative was
> recognized (make sure you have at least one group in each
> alternative).
Yes, but in a Python program it's more straightforward to program
in Python. ;)
But this is from a grade A regex avoider, so take it with a small
chunk of sodium.
>> Is it possible to somehow test for a match, as well as do assignment
>> of the re match object to a variable?
One way to attack this problem that's not yet been explicitly
mentioned is to match using a generator function:
def match_each(s, re_seq):
for r in re_seq:
yield r.match(s)
And later something like:
for match in match_each(s, (expression1, expression2, expression3)):
if match:
print(match.groups()) # etc...
--
Neil Cerutti
--
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