Tim Chase <python.list <at> tim.thechases.com> writes: > it's because you're taking a snapshot copy of "a" in the middle of > the loop. In your first example, if you change it to > > results = [] > for i in a[:-1]: > results.append(a.pop() and a) > print results > > you get the same thing as your list comprehension because each item > in "results" refers to the now-(mostly)empty "a". > > -tkc > >
Hi Tim, and thanks a lot for helping! I got it: in the comprehension case I'm only getting my results at the end, when my list has been emptied! Thanks, I got stuck with this, but now it's obvious. Best, Wolfgang -- http://mail.python.org/mailman/listinfo/python-list
