On 27 March 2013 08:27, Peter Otten <__pete...@web.de> wrote: > Look again, for the grouper() recipe. For lists you can also use slicing: > >>>> items > ['a', 'b', 'c', 'd', 'e', 'f', 'g'] >>>> n = 3 >>>> [items[start:start+n] for start in range(0, len(items), n)] > [['a', 'b', 'c'], ['d', 'e', 'f'], ['g']]
Another way with islice (so it works for any iterable): >>> from itertools import islice >>> items = ['a', 'b', 'c', 'd', 'e', 'f', 'g'] >>> n = 3 >>> list(iter(lambda i=iter(items):list(islice(i, n)),[])) [['a', 'b', 'c'], ['d', 'e', 'f'], ['g']] Not too readable though :) -- Arnaud -- http://mail.python.org/mailman/listinfo/python-list
